package com.swift.service.role;

import com.swift.core.role.Role;

/**
 * @author Administrator
 * @description :
 * @date 2022/06/18 16:20
 * @since open jdk 1.8
 */
public interface RoleService {
    /**
     * @description 根据id查询用户角色信息
     * @param rid rid
     * @return User
     */
    public Role queryRoleInfoById(int rid);
}
